567=(2x)^2/7-x

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Solution for 567=(2x)^2/7-x equation: 


x in (-oo:+oo)

567 = ((2*x)^2)/7-x // - ((2*x)^2)/7-x

x-(((2*x)^2)/7)+567 = 0

x-4/7*x^2+567 = 0

DELTA = 1^2-(-4/7*4*567)

DELTA = 1297

DELTA > 0

x = (1297^(1/2)-1)/(-4/7*2) or x = (-1297^(1/2)-1)/(-4/7*2)

x = -7/8*(1297^(1/2)-1) or x = 7/8*(1297^(1/2)+1)

x in { -7/8*(1297^(1/2)-1), 7/8*(1297^(1/2)+1) }

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